buf.writeUInt16LE(value[, offset])

• value <integer> 要写入 buf 的数字。
• offset <integer> 开始写入之前要跳过的字节数。 必须满足 0 <= offset <= buf.length - 2。 默认值: 0。
• 返回: <integer> offset 加上写入的字节数。

将 value 作为小端序写入 buf 中指定的 offset。 value 必须是有效的无符号 16 位整数。 当 value 不是无符号 16 位整数时，则行为未定义。

此函数也可在 writeUint16LE 别名下使用。

const buf = Buffer.allocUnsafe(4);

buf.writeUInt16LE(0xdead, 0);
buf.writeUInt16LE(0xbeef, 2);

console.log(buf);
// 打印: <Buffer ad de ef be>

• value <integer> Number to be written to buf.
• offset <integer> Number of bytes to skip before starting to write. Must satisfy 0 <= offset <= buf.length - 2. Default: 0.
• Returns: <integer> offset plus the number of bytes written.

Writes value to buf at the specified offset as little-endian. The value must be a valid unsigned 16-bit integer. Behavior is undefined when value is anything other than an unsigned 16-bit integer.

This function is also available under the writeUint16LE alias.

const buf = Buffer.allocUnsafe(4);

buf.writeUInt16LE(0xdead, 0);
buf.writeUInt16LE(0xbeef, 2);

console.log(buf);
// Prints: <Buffer ad de ef be>