url.parse(urlString[, parseQueryString[, slashesDenoteHost]])
¥Stability: 3 - Legacy: Use the WHATWG URL API instead.
- 
urlString<string> 要解析的 URL 字符串。¥
urlString<string> The URL string to parse. - 
parseQueryString<boolean> 如果为true,则query属性将始终设置为querystring模块的parse()方法返回的对象。如果为false,则返回的网址对象上的query属性将是未解析、未解码的字符串。默认值:false。¥
parseQueryString<boolean> Iftrue, thequeryproperty will always be set to an object returned by thequerystringmodule'sparse()method. Iffalse, thequeryproperty on the returned URL object will be an unparsed, undecoded string. Default:false. - 
slashesDenoteHost<boolean> 如果为true,则字面串//之后和下一个/之前的第一个令牌将被解释为host。例如,给定//foo/bar,结果将是{host: 'foo', pathname: '/bar'}而不是{pathname: '//foo/bar'}。默认值:false。¥
slashesDenoteHost<boolean> Iftrue, the first token after the literal string//and preceding the next/will be interpreted as thehost. For instance, given//foo/bar, the result would be{host: 'foo', pathname: '/bar'}rather than{pathname: '//foo/bar'}. Default:false. 
url.parse() 方法接受网址字符串,解析并返回网址对象。
¥The url.parse() method takes a URL string, parses it, and returns a URL
object.
如果 urlString 不是字符串,则抛出 TypeError。
¥A TypeError is thrown if urlString is not a string.
如果 auth 属性存在但无法解码,则抛出 URIError。
¥A URIError is thrown if the auth property is present but cannot be decoded.
url.parse() 使用一种宽松的、非标准的算法来解析 URL 字符串。它很容易出现安全问题,例如 主机名欺骗 和用户名和密码的不正确处理。
¥url.parse() uses a lenient, non-standard algorithm for parsing URL
strings. It is prone to security issues such as host name spoofing
and incorrect handling of usernames and passwords.
url.parse() 是大多数旧版 API 的例外。尽管存在安全问题,但它是旧版的并且没有被弃用,因为它是:
¥url.parse() is an exception to most of the legacy APIs. Despite its security
concerns, it is legacy and not deprecated because it is:
- 
比替代的 WHATWG
URL解析器更快。¥Faster than the alternative WHATWG
URLparser. - 
与替代的 WHATWG
URLAPI 相比,相对 URL 更易于使用。¥Easier to use with regards to relative URLs than the alternative WHATWG
URLAPI. - 
在 npm 生态系统中广泛依赖。
¥Widely relied upon within the npm ecosystem.
 
谨慎使用。
¥Use with caution.